Question

two capacitors c1=6if and c2=12uf are in series across a 180 volts d.c supply. calculate the charges on c1 and c2

Answer 1

As per the question, the capacitors are connected in series.

It is given that  $c_{1} =6\mu F$

                         $c_{2}=12\mu F$

The supply voltage v = 180 volts.

The net capacitance of the circuit is calculated as -

                                  $\frac{1}{c} =\frac{1}{c_{1}}+ \frac{1}{ c_{2}}$

                                  $c=\frac{c_{1} c_{2}} {c_{1} +c_{2}}$

                                        $=\frac{6\times 12}{6+12}\mu F$

                                        $=4\mu F$

                                        $=4\times 10^{-6}F$

The charge flowing across the circuit is calculated as -

                                  $charge\ q=cv$

                                                     $=\ 4\times 10^{-6}F\times 180\ volts$

                                                     $=72\times 10^{-5}C$

We know that charge remains the same during series connection of capacitors.

Hence, the charge on each capacitor is $72\times 10^{-5}C$

                                                     

                                       

Answer 2

Answer:

answer is 120 and 60 volt