Question

two capacitors c1 and c2 are connected across 200V battery. the potential drop across c1 is 120V .a capacitor of capacitance 2uf is connected in parallel with c1 and the potential drop across c2 becomes 160 V.what are the values of c1 and c2??​

Answer 1

Explanation:

Initially the charge is same on both capacitors.

Therefore, 120C1 = 80C2 .

Afterwards ( C1 + 2 ) 40 = 160 C2

This gives C1= 0.4 Micro F and 0.6 Micro F.