Question

Two capacitors connected in series C1: 100uF, 25V and C2: 300uF, 35V, both are supplied
by E= 100V. Verify which capacitor will be damaged

Answer 1

The correct answer is Capacitor C1 would  have suffered from damage. The voltage passing through it is 75V which is greater than the required voltage of 25V.

Explanation:

• Since we know the two capacitors are linked to one another and the given values are C1 = 100uF, 25V and C2 = 300uF, 35V. Here voltage is 100V.

• Now we will calculate the total capacitance of the capacitors using the formula Cr = 1/C1 + 1/C2

• $= \frac{C_{1} * C_{2} }{C_{1} + C_{2} } = \frac{100uF * 300uF}{100uF + 300uF} = 75uF$

• Now we can find the drop in voltage as such $V_{c1} = \frac{C_{T} }{C_{1} } × E$.

• By putting in the values we get 75V.

• So, $V_{C2} = \frac{C_{T} }{C_{2} } × 100$ = 25V