Question

Two capacitors each having capacitance C and breakdown voltage V are joined in series. The capacitance and the breakdown voltage of the combination will be
(a) 2 C and 2 V
(b) C/2 and V/2
(c) 2 C and V/2
(d) C/2 and 2 V.

Answer 1

Answer:

hiii

your answer is here. !

Explanation:

In series arrangement at charge on each plate of each capacitor has the same magnitude the potential difference in distributed inversely in the ratio of capacitor ie,

V=V1+V2

V=2V

The equivalent capacitance C's is given by

1/Cs=1/C1+1/C2

Cs=C/2

answer is

2V and C/2

option D is right answer. !

follow me ?

Answer 2

Answer:

Explanation:

In series arrangement at charge on each plate of each capacitor has the same magnitude the potential difference in distributed inversely in the ratio of capacitor

V=V1+V2

V=2V

The equivalent capacitance C's is given by

1/Cs=1/C1+1/C2

Cs=C/2

answer is

2V and C/2

option D is right answer.