Question

two capacitors each of capacitance 10f are connected in prallel calculate the capacitance

Answer 1

Answer:

$\boxed{\sf Net \ capacitance \ of \ the \ combination = 20 \ F}$

Given:

Capacitance of two capacitor connected in parallel = 10F

i.e.

$\sf C = C_1 = C_2 = 10 \ F$

To Find:

Net capacitance of the combination

Explanation:

Net capacitance in parallel combination:

$\sf \boxed{ \bold{C_{net} = C_1 + C_2}}$

Substituting values;

$\sf \implies C_{net} = 10 + 10$

$\sf \implies C_{net} =20 \: F$

Answer 2

Answer:

$\bigstar{\bold{Capacitance\:=\:20\:F}}$

Explanation:

$\Large{\underline{\underline{\bf{Given:}}}}$

• Two capacitors of capacitance 10 F connected in parallel

$\Large{\underline{\underline{\bf{To\:Find:}}}}$

• Total capacitance

$\Large{\underline{\underline{\bf{Solution:}}}}$

→ Since the capacitors are connected in parallel, total capacitance is given by

C = C₁ + C₂

→ Substituting the given datas we get,

 C  = 10 + 10

 C = 20 F

$\boxed{\bold{Capacitance\:=\:20\:F}}$

$\Large{\underline{\underline{\bf{Notes:}}}}$

→ If the capacitors are connected in parallel, total capacitance is given by

  C = C₁ + C₂ + C₃+......

  In a parallel connection, voltage across each conductor is same but charge is different.

→ If the capacitors are connected in series, total capacitance is given by

 $\dfrac{1}{C} =\dfrac{1}{C_1}+\dfrac{1}{C_2} +......+\dfrac{1}{C_n}$

 In a series connection charge across each conductor is same but voltage is different.