Two capacitors each of capacitance 2 M F are connected in series between the points A and B.Another parallel combination of two
capacitors each of capacitance C is connected between A and B. If the effective capacitance
between A and B is 9 MF, then C has a value of
a) 1 MF
b) 2 MF
c) 3 MF
d) 4 MF
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Explanation:
When two capacitors of capacitance 2μF are in parallel , the equivalent capacitance is
C
eq
=2+2=4μF. Now it is connected to 12μF in series . So the capacitance of system is C
sys
=
4+12
4×12
=3μF
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