Question

Two capacitors have a capacitance of 5mf when connected in parallel and 1.2 mf when connected in series calculate their capacitance

Answer 1

first two are in parallel so 10mf

and then 1.2 in series

the. 1/10 + 1/1.2

Answer 2

The value of capacitors are 2 mF and 3 mF. Hence, this is the required solution.

Explanation:

Let $C_1\ and\ C_2$ are two capacitors. The equivalent capacitance of capacitors when connected in parallel is given by :

$C_p=C_1+C_2$

$5\ mF=C_1+C_2$.............(1)

The equivalent capacitance of capacitors when connected in series is given by :

$\dfrac{1}{C_s}=\dfrac{1}{C_1}+\dfrac{1}{C_2}$

$C_s=\dfrac{C_1C_2}{C_1+C_2}$

$1.2\ mF=\dfrac{C_1C_2}{C_1+C_2}$..............(2)

On solving equation (1) and (2) we get :

$C_1=2\ mF$

And $C_2=3\ mF$

So, the value of capacitors are 2 mF and 3 mF. Hence, this is the required solution.

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