Physics, asked by kvamsiprasad183, 1 month ago

Two capacitors of 10 µF each connected in parallel. The combination is further connected in series with two capacitors of 2 µF and 5µF. Calculate the total capacitance of the circuit.​

Answers

Answered by michael4322
0

Answer:

Generally, any number of capacitors connected in series is equivalent to one capacitor whose capacitance (called the equivalent capacitance) is smaller than the smallest of the capacitances in the series combination.

Explanation:

Answered by Ishaan038
0

Answer: The answer to this question is-

Two capacitors of 10 µF each connected in parallel. Their equivalent capacitance is as below-

C_{eq} = C_{1} + C_{2}

C_{eq} = 10 + 10

C_{eq} = 20µF

And it is connected in series with two capacitors of 2 µF and 5µF.

\frac{1}{C_{eq} } = \frac{1}{C_{1} } + \frac{1}{C_{2} } + \frac{1}{C_{3} }

C_{eq} = \frac{4}{3}

Explanation:

Capacitors in Parallel

Capacitors are independently connected to the same voltage source when they are connected in parallel. Because each capacitor is directly connected to the battery, the voltage of the parallel capacitors is the same as the voltage source even though the charge on each capacitor fluctuates. The capacitance that numerous capacitors would have if their capacitances were merged into a single capacitor is known as the equivalent capacitance. When capacitors are connected in parallel, their equivalent capacitance is greater than the total of their individual capacitances.

C_{eq} = C_{1} + C_{2}

Capacitors in Series

When capacitors are linked in series, they are all connected to the same voltage source via the same path. To add capacitors in series, simply connect each one in a line. Capacitors connected in series have identical charges, but the sum of the individual voltages across all capacitors equals the voltage of the voltage source. The total of the inverse capacitances of each capacitor makes up the equivalent capacitance of capacitors connected in series, which is less than each capacitor's individual capacitance.

\frac{1}{C_{eq} } = \frac{1}{C_{1} } + \frac{1}{C_{2} }

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https://brainly.in/question/19393085

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