Two capacitors of 3 uF
are joined in parallel across a
battery of 15 volts, the charge
stored by each will be:
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Given : Two capacitors of 3 μF are joined in parallel across a battery of 15 volt
To Find : the charge stored by each will be
Solution:
Q = CV
in Parallel Circuit Voltage will be same across each capacitor
Hence Voltage across each capacitor = 15 V
Each capacitor = 3 μF
C = 3 μF
V = 15 V
Q = 3 x 15 = 45 μCoulomb
charge stored by each will be = 45 μCoulomb
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