Question

two capacitors of capacitance 100 microfarad and 200 uF are connected in series. A potential difference of 90v is supplied across them. calculate the potential and charge across each capacitor.
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Answer 1

Answer:

In series, potential difference distributes in inverse ratio of capacitance.

∴

V

B

V

A

=

C

A

C

B

=

C

1

C

2

=

40

60

=

2

3

∴C

2

=1.5C

1

.....(i)

Now

V

B

′

V

A

′

=

C

A

′

C

B

′

or

90

10

=

(C

1

+2)

C

2

or C

1

+2=9C

2

....(ii)

Solving Eqs. (i) and (ii), we get

C

1

=0.16μF and C

2

=0.24μF