two capacitors of capacitance 100 microfarad and 200 uF are connected in series. A potential difference of 90v is supplied across them. calculate the potential and charge across each capacitor.
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Answer:
In series, potential difference distributes in inverse ratio of capacitance.
∴
V
B
V
A
=
C
A
C
B
=
C
1
C
2
=
40
60
=
2
3
∴C
2
=1.5C
1
.....(i)
Now
V
B
′
V
A
′
=
C
A
′
C
B
′
or
90
10
=
(C
1
+2)
C
2
or C
1
+2=9C
2
....(ii)
Solving Eqs. (i) and (ii), we get
C
1
=0.16μF and C
2
=0.24μF
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