Question

Two capacitors of capacitance 3uf and 5uf are joined in parallel and the combination is connected in series with 2uf capacitor. What is the resultant capacitance?

Answer 1

Explanation:

1.6 in parellel c+c and in series 1/c+1/c and than find equivalent capacitance

Answer 2

Explanation:

GIVEN :-

Capacitor , c₁ = 2µF.

Capacitor , c₂ = 3µF.

Capacitor , c₃ = 5µF.

TO FIND :-

Equal capacitance of the combination.

SOLUTION :-

As we know that when the capacitors are connected in series combination the equivalent capacitance is given by,

$: \implies \displaystyle \sf \: \frac{1}{c_{eq}} = \frac{1}{c_1} + \frac{1}{c_2} + \frac{1}{c_3} + .... + \frac{1}{c_n}$

$: \implies \displaystyle \sf \: \frac{1}{c_{eq}} = \frac{1}{2 \mu F} + \frac{1}{3 \mu F } + \frac{1}{5 \mu F}$

$: \implies \displaystyle \sf \: \frac{1}{c_{eq}} = \frac{15}{30\mu F} + \frac{10}{30 \mu F } + \frac{6}{30 \mu F}$

$: \implies \displaystyle \sf \: \frac{1}{c_{eq}} = \frac{31}{30\mu F}$

$: \implies \displaystyle \sf \: c_{eq} = \frac{30\mu F}{31}$

$: \implies \displaystyle \sf \: c_{eq} =0.96\mu F$

$: \implies \underline{ \boxed{ \displaystyle \sf \: c_{eq} \approx 1\mu F}}$

$\therefore{ \underline{\sf Equal \: capacitance \: of \: the \: combination \: is \: d) \: 1 \mu F}}$