Question

two capacitors of capacitance 6 microfarad a and 3 microfarad are connected in series and potential difference of 9000 volt is applied across the combination they are then disconnected and Re connected in parallel calculate the potential difference between the plates​

Answer 1

Answer:

In series combination,

C1=6,C2=3,V=9000v

Ceq=C1.C2/(C1+C2)

Ceq=2

So,Q=CV

2*9000=18000 microcoulomb

And now in parallel combination,

Ceq=C1+C2=6+3=9

so,V=Q/C

18000/9=2000V

Hence,in parallel combination potential difference between plates is 2000V.