Physics, asked by nishant262, 18 days ago

Two capillaries made of same material but of different radi
are dipped in a liquid. The rise of liquid in one capillary is
2.2 cm and that in the other is 6.6 cm. The ratio of their
radii is
IMP PET 1990)
(a) 9:1
(b) 1:9
(c) 3:1
(d) 1:3​

Answers

Answered by divyameher00
0

Answer

The rise of liquid in one capillary is 2.2 cm and that in the other is 6.6 cm.

Explanation:

The ratio of their radii is [MP PET 1990] A) 9 : 1.

Answered by dayanidhisharma19
0

Answer :

The ratio of their radii is 3 : 1

Step-by-step Explanation :

Given : 1) Rise of liquid one capillary H1 = 2.2 cm,

2) Rise of liquid second capillary H2 = 6.6 cm

To find : Ratio of their radii = ?

Height of liquid in a capillary tube is,

H = 2T/ ρgr

(where T is surface tension of fluid)

The capillary rise is inversely proportional to the tube radius.

H α 1/R

Therefore H1 × R1 = H2 × R2

2·2 × R1 = 6·6 × R2

The ratio of radii = R1/R2 = 6.6/2.2 = 3/1

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