two car leave delhi at the sane time, travelling in opposite direction. if the average speed of one car is 5 km/hr more than that of the other and they are 453 km apart at the end of 5 hrs, what is the average speed of each?
pohordebbarma:
please some one help me is there anyone
Answers
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You can add their speeds to get the speed
at which they are moving apart
Let that speed = +s+%2B+s+%2B+5+
+425+=+%28+2s+%2B+5+%29%2A5+
+425+=+10s+%2B+25+
+10s+=+400+
+s+=+40+
+s+%2B+5+=+45+
Their average speeds are 40 km/hr and 45 km/hr
Answer by mananth(15050) (Show Source): You can put this solution on YOUR website!
Car I x kmph
Car II x+ 5 kmph
..
They are moving away from each other
So add up their speed.
combined speed = x+x+5
(2x+5)
Time = 5 hours
Distance = 425 km
Distance = speed * time
(2x+5 )* 5 = 425
10 x + 25 = 425
10 x = 425 + -25
10 x = 400
/ 10
x= 40 kmph Car I
Car II 40 + 5 = 45 kmph
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