Question

Two cards are drawn at random from a 52 card deck, what is the probability of getting exactly one ace?

Answer 1

Let S be sample space
n(S) = no. of ways of drawing 2 cards
n(S) = 52C2 = (52*51)/2 = 26*51 = 1326

E be Event of drawing exactly one ace

Possible case:
One is ace and the other is non ace.
{ In a deck of cards, there are 4 aces and (52-4) i.e,. 48 non aces }

n(E) = no. of ways of drawing exactly one ace
n(E) = 4C1 * 48C1= 4*48 = 192
n(E) = 192


Probability = n(E)/n(S) = 192 / 1326

•°•Required probability = 192/1326

You can reduce this fraction to lowest terms .


;)
hope it helps ...