Two cards are drawn at random from a well shuffled deck of 52 cards. Find the probability that these are (i) both red cards, (ii) both spade cards, (iii) both queens, (iv) one heart and one diamond card, (v) one king and one ace card when (1) the cards are drawn at a time. (2) the cards are drawn one by one with replacement. (3) the cards are drawn one by one without replacement. pls solve it jaldi...
Answers
Answer:
n=52
i) King of red colour can be hearts King or a diamond king.
So, the possibility is 2.
P(Red king)=
52
2
=
26
1
ii) A face card can be jack, queen, king of any suite.
In this way we will get 3×4=12 face cards.
P(Face card)=
52
12
=
13
3
iii) A red face card can be either hearts or diamond king, jack or queen, which means there are 3×2=6
P(Red face card)=
52
6
=
26
3
iv) There is only one Jack of hearts.
P(Jack of hearts)=
52
1
v) There are 13 spades in total.
So, P(Spade)=
52
13
=
4
1
vi) There is only one queen diamond.
Hence, P(Queen diamond)=
52
1
Answer:
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Step-by-step explanation:
ANSWER
In 52 cards getting a one card as 52 times
a.(1) The king in card is two getting in 2 times
Then probability =522=261
(ii)In 52 cards the king ,queen and joker are three face card.Then total face cards are 12.So these card get 12 times
Then probability =5212=133
(!!!)In 52 cards the red face card are 3 face card.Then total
red face cards are 3.So these card get 6 times
Then probability =526=263
(iv)In 52 cards the jack of heart card is one .So the getting time card is one
Then probability =$$\frac{1}{52}
(b) (i)In 52 cards the spade cards are 13. So getting time is 13
Then probability =5213=41
(ii)In 52 cards the queen of diamonds is one .So getting time is one
Then probevility=521
(iii)In 52 cards Neither a red card nor a queen the total cards are
24.So time of getting cards are 24
Then probability =5224=136
(c) (i)In 52 cards non-face cards are 40.So timie of getting cards are 40.
Then probability =5224=136
(ii)In 52 cards a black king or a red queen are 4.So getting time is 4.
Then probability =524=131