Question

Two cards are drawn at random from an ordinary pack of cards. Find the probability that they will
consist of an Ace and a seven.​

Answer 1

Answer:

Please find the attachment

Answer 2

The required probability of getting an ace and a seven will be 8/663

GIVEN: Two cards are drawn at random from an ordinary pack of cards.
TO FIND The probability that they will consist of an Ace and a Seven.
SOLUTION:

As we are given in the question,

Two cards are drawn at random from an ordinary pack of cards.

As we know,

A normal pack of 52 cards is given.

Also,

There are 26 black and 26 red cards.

Out of these 26 red cards, 13 are diamonds and 13 are hearts.

Out of these 26 black cards, 13 are spades and 13 are clubs.

Also,

We have 4 aces and 4 cards of seven.

We know,

Number of ways of getting an ace and one seven = 4c1 * 4c1

Number of ways of getting an ace and one seven = 4 * 4

Number of ways of getting an ace and one seven = 16

Therefore,

Required probability = 16/52c2

= 16*2/52*51

= 8/663

Therefore,

The probability of getting an ace and a seven will be 8/663.

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