Question

Two cards are drawn simultaneously from a well shuffled pack of 52 cards find the mean and variance of the number of red cards

Answer 1

X can take values 0,1,2

P(X=0) = Probability of getting no red card

=2652×2551

=2651

P(X=1) = Probability of getting one red card

=2652×2651+2652×2651

=2651

P(X=2) = Probability of getting both red card

=2652×2551=25102

x=0=>P(x=x)=25102

x=1=>P(x=x)=2651

x=2=>P(x=x)=25102

E(x)=0×25102+1×2651+2×25102

=2651+50102=52+50102

=102102=1

∑P1x21=0×25102+1×2651+4×25102

=2651+100102=102+100102

=202102

Mean =∑P1wi=1

Variance =∑Pix21−(∑Pixi)2

=202102−1

=100102=5051

Answer 2

Answer:

Step-by-step explanation:

Hope this helps

Total no. of cards in the deck = 52

Number of red cards = 26

No. of cards drawn = 2 simultaneously

X = value of random variable = 0, 1, 2