two cards are selected at random from 10 cards numbered 1 to 10 find the probability p that sum is odd.,if two cards are drawn one after another without replacement?
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probability p that sum is odd = 5/9
Step-by-step explanation:
two cards are selected at random from 10 cards numbered 1 to 10
2 Cards can be selected in ¹⁰C₂ = 45 Ways
Sum is odd if 1 Number is odd and another number is Even
1 , 3 , 5 , 7 , 9 - odd
2 , 4 , 6 , 8 , 10 - Even
⁵C₁ * ⁵C₁ = 25 Ways
probability p that sum is odd = (25/45) = 5/9
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