Physics, asked by FriendlySweety, 6 months ago

Two carnot engines a and b have their sources at 327 and 227 and sinks at 127 and 27 ratio of efficiency of a to that of b​

Answers

Answered by itzIntrovert
6

\huge\bigstar\underline\pink{Answer}

efficiency of Carnot Engine is given by

n = (T1-T2)/T1

where,

n = efficiency

T1 = Temperature of source

T2 = Temperature of Sink

⚫ Efficiency of Carnot Engine a =>

n = (327-127)/327

n = 200/327

⚫ Efficiency of Carnot Engine b =>

n = (227-27)/227

n = 200/227

There ratio (a/b) = 227/327

Happy to help

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