Question

Two cars A and B approach a stationary observer from opposite sides as shown in figure.Observer hears no beats. If the frequency of the horn of the car B is 504 Hz the frequency of horn of car A will be (V = 330 m/s) ft​

Answer 1

Answer:

529.2Hz

Explanation:

Since, the person hears no beats therefore their apparent frequency are the same.

So, n×

330−15

330

=504×

330−30

330

n=

300

504×315

=529.2Hz

Answer 2

Answer:—

• 529.2Hz

Step by Step Explanation:—

From Doppler's effect the apparent change in frequency of a wave that is preceived by the stationary observer is

• n' = n↓o [V/V - Vs]

Where,

V is the speed of sound

Since,

Observer is not hearing any beats, the apparent frequency of the two cars should be equal.

Hence,

• n' = n"

→ 504(V/V - 30) = n(V/V - 15)

→ n = (330 - 15)/(330 - 30) × 504

→ n = 315 × 504/300

→ n = 529.2Hz

Hence,

n = 529.2 Hertz.

@vikramjeeth.