Question

Two cars A and B are 500m apart from each other.car B is ahead of car A. They are moving in the same direction and the same peed of 10km/s If veachle A is accelerated by 4km/s^2 and car B is having same speed as earlier find at what distance Car A and B will meet​

Answer 1

Answer:

they will meet at 20 minutes

Answer 2

Given:

Two cars A and B are 500m apart from each other. Car B is ahead of car A. They are moving in the same direction and the same peed of 10km/s Vehicle A is accelerated by 4km/s².

To find:

Distance after which they will meet ?

Calculation:

Let time after which they will meet be t :

So, after time t , position if car A and B will be same.

$\therefore \: d_{A} = d_{B} + 0.5$

$\implies \: (u_{A}t + \dfrac{1}{2} a_{A} {t}^{2} ) = (u_{B} \times t) + 0.5$

$\implies \: (10t + \dfrac{1}{2} 4{t}^{2} )= (10 \times t) + 0.5$

$\implies \: (10t + 2{t}^{2} ) = (10 t) + 0.5$

$\implies \: 2{t}^{2} = 0.5$

$\implies \: {t}^{2} = 0.25$

$\implies \: t = 0.5 \: sec$

Distance travelled by car B after which it will meet will be :

$\therefore \: d_{B} = 10 \times 0.5$

$\implies\: d_{B} = 5 \: km$

So, car A and B will meet after car B travels for 5 km.