Question

two cars A and B are at positions 100m and 200m from the origins at time t=0.they start simultaneously with velocities 10m/s and 5m/s respectively. the car A will overtake the car B at a distance of? please answer it with explanation

Answer 1

Relative distance between Car A and Car B = 200m-100m = 100m
after time t both will simultaneously start since velocity of A is greater than B .
A will overtake car B after some time let that time will be T

A should cover distance 100m with relative velocity after some time T
Vab = velocity of A with respect to the B = Va - Vb = 10 - 5 = 5m/s

Velocity = distance/time
Vab = Dr/T
T = 100/5
T = 20 s

at T = 20s , with velocity = 10m/s
distance travelled from car A = S
V = d/T
d = VT
d = 10×20 = 200m

from the origin distance to the car A
= 100m + 200m
= 300m .

Answer 2

Answer:

Explanation:

X_bo=200m,    X_ao=100m   ,   V_a=10m/s,    V_b=5m/s

Now X_b-X_a = (X_bo-X_ao)+(V_b-V_a)*t

suppose at t=t both car will over take each other

• therefore