Question

Two cars A and B are at rest at same point initially. If a starts with uniform velocity of 40 metre per second and B starts in same direction with constant acceleration of 4 metre per second square ,then B will catch A after how much time ?

Answer 1

Let distance covered by A be S1
Let distance covered by B be S2

B will catch A when S1 = S2
S = ut + 1/2 * a * t^2
Therefore, 

40t + (1/2 * 0 * t^2) = 0t + 1/2 * 4 * t^2
40t = 2t^2
20t = t^2

Therefore, t = 20

Answer 2

Answer:

Explanation:

Let distance covered by A be S1

Let distance covered by B be S2

B will catch A when S1 = S2

S = ut + 1/2 * a * t^2

Therefore, 

40t + (1/2 * 0 * t^2) = 0t + 1/2 * 4 * t^2

40t = 2t^2

20t = t^2

Therefore, t = 20

Read more on Brainly.in - https://brainly.in/question/1231455#readmore