Question

Two cars A and B are initially 250 m apart such that A is behind car B. The car A is moving with uniform velocity of 10 m/s towards B and the car B starts moving away from A with constant acceleration of 0.2 / m s . The time at which separation between the cars will be zero.​

Answer 1

Answer:

2

Explanation:

after 2 seconds they will meet

Answer 2

Answer:

50 seconds

Explanation:

Distance traveled by car B = 1/2*0.2*t^2

=0.1*t^2

Distance traveled by car A = 10t

ATQ

0.1t^2+250=10t

1t^2+2500=100t

1t^2-100t+2500=0

1t^2-50t-50t+2500=0

t(t-50)-50(t-50)=0

t-50=0

t=50