Question

Two cars a and b are moving west to east and south to north respectively along crossroads.a moves 72km/h and is 500m away from cross road and b moves 54km/h and is 400m away from the cross road .find the shortest distance between them.

Answer 1

$\textbf {Hey there, here is the solution.}$

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Car A is 500m is east of the crossroad.

Car B is 300m south of the crossroad.

The shortest distance will be the diagonal distance between there.

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Find the shortest distance:

a² + b² = c²

c² = 500² + 400²

c² = 410,000

c = √410,000

c =640 m

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Answer: The shortest between them is 640m

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⭐$\textbf {Cheers }$⭐

Answer 2

Hello here is your answer by Sujeet yaduvanshi ☝☝☝☝☝☝☝☝☝☝☝☝☝☝☝


Solution:-

Given:-)
Car A is travelled in the Direction of West to North=500 metre

Car B is travelled in the Direction of South to North =400 metre

then,

Using Pytogoras theorem

we know that Pythagorean theorem,

So,

GIVEN :-base and perpendicular

Again,

H²=P²+B²

H²=500²+400²

H²=410000

H=√410000

H=640.31