Question

Two cars A and B are moving with same speed of 45 km/h along the same direction. If a third car C coming from opposite direction with a speed of 36 km/h meets twocars in an interval of 5 minutes, the distance of separation of two cars A and B should be (in km)

Answer 1

Answer:

V  A =V   B =45km/hr

V  C  =36km/hr

Let x is the distance between A and B.

Velocity of approach between A and B.

⇒V  AC  =V A  +V B  =(45+36)km/hr=81km/hr

    V BC =V  B+V  C =(45+36)km/hr=81km/hr

⇒ Velocity of approach =  

Time difference in meeting A and B/Distance between A and B

​  

 

⇒△t=5min= 5 /60

⇒81=  x×60/5

​⇒x=5×81/60

=6.75km

Hence, the answer is 6.75km.