two cars a and b are travelling with speed v1 and v2. when they travel in same direction the seperation between them increases at rate of 4m/s and if they go in the opposite direction the seperation decreases at a rate of 6m/s. the speed of v1 and v2 are?
Answers
Answered by
1
Answer:
v1+v2=6m/s
v1-v2=4m/s
on calculating
v1=5m/s
v2=1m/s
Answered by
0
Answer:
V1+v2 =6 (I)
V1 -v2 = 4 (ii)
Explanation:
additing I and ii
V1 + v2 =6
V1 - v2 = 4
2 (v1) = 10
V1 = 10÷2
V1 = 5
place V1 in eq 1
5 -v2 = 6
- v2 = 6 -5
v2 = 1
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