Two cars A and B cross a point p with velocities 10m/s and 15m/s after some time car A overtakes B with a speed of 25m/s the velocity of B is
Answers
Answered by
5
Hello Dear,
● Answer -
v'B = 30 m/s
◆ Explaination -
Initially, Relative velocity of car A w.r.t. car B is -
vBA = vB - vA
vBA = 15 - 10
vBA = 5 m/s
At the time when car A overatakes car B,
vBA = v'B - v'A
v'B = vBA + v'A
v'B = 5 + 25
v'B = 30 m/s
Therefore, velocity of B at instant of overtake is 30 m/s.
Thanks for asking. Hope I helped..
Answered by
0
Explanation:
velocity = 0 m/s
speed = 10 m/s
She comes back to the initial point so displacement is 0 m.
and velocity = displacement / time = 0 / 40 = 0 m/s
and speed is total distance / time which is 400 / 40 = 10 m/s
c)speed 10m/s, velocity 0✔
Similar questions