Two cars A and B move in the same direction. At time t = 0 their respective speeds and accelerations are 1 m/s and 3 m/s, and 2 m/s2 and 1 m/s2. If the car A is at 1.5 m behind B at t = 0, when does
the car A catch the car B?
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Explanation:
Distance traveled by car A=S
A
Distance traveled by car B=S
B
According to formula S=ut+
2
1
at
2
S
A
=0t+
2
1
×2t
2
S
B
=10t+
2
1
×0t
2
Car A will overtake car B when
S
A
=S
B
+100
Putting the value S
A
and S
B
+2=10t+100
+2−10t−100=0
After solving for t, we get
t=16.18sec possible
t=−6.10sec not possible
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