Question

Two cars A and B (starting at the same time, from the same point )are moving with average speed of 40 km/h ,respectively, in the same direction. find how far will car B be from car A after 3 hours.​

Answer 1

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Answer 2

Answer:

Let two cars are A and B.

V

A

=50km/hr

V

B

=40km/hr

V

C

=xkm/hr

After t hours, car C catches second car B. So distance travelled by car C in t second is xt and this distance will be equal to distance travelled by car B in t+

2

1

hr.

So, xt=40x×(t+

2

1

)

⟹xt−40t=20

⟹t=

x−40

20

Car C will cover distance in (t+1.5hr)=x(t+

2

3

)= distance covered by car A in (t+2hr).

x(t+

2

3

)=50x(t+2)

xt+1.5x=50t+100

t(x−50)=100−1.52

20×(x−50)=100−1.5x

x−40

On solving, we get x=60km/hr.

Explanation:

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