Two cars A and B starts from the same point.
Car A moves with uniform speed of 40ms-'
and car B starts from rest with an accelera
tion of 2ms-7. If car B starts at t=0 and car A
starts from the same point at t=10s, then the
time during the journey in which car A was
ahead of car B is
Answers
Answered by
1
Answer:
This is ur answer.....
I hope this may be clear to you....
And may satisfy you...
Explanation:
We can get this answer by putting the second equation of motion
i.e
s = ut + 1/2 a( t×t)
The explanation is given clearly in the photos....
With figure explanation
So, T=20 seconds
Attachments:
Similar questions