Two cars A and B travel from one City to another City at speeds of 60kmph and 108kmph respectively. If car B takes 2 hours less time than car A for the journey. Then what is the distance (in km) between the two cities?
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Step-by-step explanation:
Answer:
270 km
Step-by-step explanation:
Let x be the distance between the City A and City B
Car 1 Case:
Distance =x
Speed of Car 1 = 60 km/hr
Time =\frac{Distance}{Speed}Time=
Speed
Distance
Time =\frac{x}{60}Time=
60
x
Car 2 Case:
Distance =x
Speed of Car 2 = 108 km/hr
Time =\frac{Distance}{Speed}Time=
Speed
Distance
Time =\frac{x}{108}Time=
108
x
Now we are given that one car takes 2 hours lesser time than the other car for the journey
So, \frac{x}{60}-\frac{x}{108}=2
60
x
−
108
x
=2
\frac{x}{135}=2
135
x
=2
x=135 \times 2x=135×2
x=270x=270
Hence the distance between City A and City B is 270 km.
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