Question

two cars a and b travel in a straight road. Car A maintain constant speed of 20 m/s and car b maintain a constant speen of 40 m/s, if b is initially 600m behind A then how far will a travel before it taken over by b​

Answer 1

Answer:

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Answer 2

Given data :

• Two cars A and B travel in a straight road.

• Car A maintain constant speed of 20 m/s and car B maintain a constant speen of 40 m/s.

• B is initially 600 m behind A then how far will A travel before it taken over by B.

Solution : according to given,

→ speed of car A = 20 m/s

→ speed of car B = 40 m/s

Here, we first need to find time taken by car B to cover distance 600 m.

By formula of speed :

→ speed = distance/time

→ 40 = 600/time

→ time = 600/40

→ time = 60/4

→ time = 15 sec

Now, {we need to find distance travel by car A in 15 sec (speed of car A = 20 m/s )}

→ speed = distance/time

→ 20 = distance/15

→ distance = 20 * 15

→ distance = 300 m .....( 1 )

According to given and from eq. ( 1 )

car A is {600 + 300} m far from car B. i.e.

car A is 900 m far from car B.

Answer : when car B cover 600 m then car A is 300 m far from B. Total disctance coverd by car B to over take car A is 900 m.

{More info : Time taken by car B when it cover distance 900 m to over take car A.

→ speed = distance/time

→ 40 = 900/time

→ time = 900/40

→ time = 45/2

→ time = 22.5 sec

Answer : 22.5 sec taken by car B when it cover distance 900 m to over take car A. }