Question

Two cars A and B travel in straight line. The distance of A from the starting point is given as function of time by xA(t)=pt+qt2 with p=2.60 m/s and q=1.20m/52. The distance of B from the starting point is xB(t)=rt2-5t3 Where r=2.8m/s^2and S=0.20m/s

Acceleration of car A is –

a) 2.4m/5^2

b) 1.2m/5^2

c) 0m/5

d) 3.6m/5^2

please give the correct answer otherwise your answer will be reported❤

please give the correct answer otherwise your answer will be reported❤​

Answer 1

Answer:

The distance of A from the starting point is given as a function of time by XA (t) = ot+ ßt, with a = 2.60 m/s and B = 1.20 m/s. The distance of B from the starting point is Xe (t) 7 - 8t", with y = 2.80 m/s' and 8 0.20 m/s.