Question

Two cars are moving along a straight line in opposite directions with speed of 10m/s and 15m/s. The magnitude of relative velocity of one car with respect to the other car is​

Answer 1

Answer:

IT IS VERY SIMPLE ... just add the velocities of both car becoz they r moving opposite to each other ...

Step-by-step explanation:

so 10+15=

= 25m/s

THANK YOU

Answer 2

Answer:

The magnitude of the relative velocity of one car to the other car is​ (Vab) = 25m/s.

Step-by-step explanation:

Given,

The speed of car A (Va) = 10m/s

The speed of car B (Vb) = 15m/s (in opposite direction to the car A)

Calculations -

The relative velocity of car A with respect to the car B (Vab) = (Va) - (-Vb) = (10) - (-15)

= 25m/s

The magnitude of the relative velocity of one car to the other car​ (Vab) is 25m/s.

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