Two cars are moving along a straight line in opposite directions with speed of 10m/s and 15m/s. The magnitude of relative velocity of one car with respect to the other car is
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Answered by
2
Answer:
IT IS VERY SIMPLE ... just add the velocities of both car becoz they r moving opposite to each other ...
Step-by-step explanation:
so 10+15=
= 25m/s
THANK YOU
Answered by
0
Answer:
The magnitude of the relative velocity of one car to the other car is (Vab) = 25m/s.
Step-by-step explanation:
Given,
The speed of car A (Va) = 10m/s
The speed of car B (Vb) = 15m/s (in opposite direction to the car A)
Calculations -
The relative velocity of car A with respect to the car B (Vab) = (Va) - (-Vb) = (10) - (-15)
= 25m/s
The magnitude of the relative velocity of one car to the other car (Vab) is 25m/s.
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