Two cars are moving in same direction with a speed of 40 km/h. They are separated by 5 km. A car is moving in opposite direction with a speed of 60 km/h. How much is the minimum time (in minutes), it will take to cross both cars?
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Answer:
They are separated by a distance of 5 km, the speed of a car moving in the opposite direction of it meets these two cars at an interval of 4 minutes, will be. So the relative separation between them (=5km) always remains the same.
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The given question can be solved by applying the concept of relative velocity.
Let the minimum time required for the cars to cross each other=t
the speed of the car A, given;
V₁=40 km/h
The speed of the car B , given;
V₂= (-60km/h)
The distance seprating the cars A and B (d) = 5 km
V₁₂=V₁ - V₂
V₁₂= 40- (-60)
V₁₂=100 km/h
Speed= distance/time
Time= distance/speed
t=d/V₁₂
t=5/100
t= 3 minutes.
Hence, the time taken for the two cars to cross each other would be 3 minutes.
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