two cars are moving in the same direction with speed of 30 km per hour they are separated by 5 km what is the speed of a car moving in opposite direction if we meet those two cars at an interval of 4 minutes
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Two cars are moving in the same direction with the same speed of 30 km/hr. They are separated by a distance of 5 km. What is the speed of a car moving in an opposite direction if it meets the two cars in an interval of 4 minutes?
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If two objects move in same direction, their relative speed will be the difference of their individual speeds.If two objects move in opposite direction, their relative speed will be the sum of their individual speeds.Distance = Speed x Time
=> If two cars are moving in same direction at same speed of 30 kmph, then relative speed is ZERO. That means, the 5km distance between them will always remain constant.
Now, if a third car travels in the opposite direction at a speed of “s”, then relative speed is s + 30.
Since it meets the two cars at an interval of 4 minutes, it means it covers a distance of 5kms in 4 minutes or 1/15 hours at a relative speed of “s + 30”.
=> 5 = (s + 30) x 1/15
=> s + 30 = 75
=> s = 45 kmph
This Speed is Relative to a Frame of Reference attached to one of the two moving cars (which are moving with constant velocity of 30kmph).
Still have a question? Ask your own!
What is your question?
If two objects move in same direction, their relative speed will be the difference of their individual speeds.If two objects move in opposite direction, their relative speed will be the sum of their individual speeds.Distance = Speed x Time
=> If two cars are moving in same direction at same speed of 30 kmph, then relative speed is ZERO. That means, the 5km distance between them will always remain constant.
Now, if a third car travels in the opposite direction at a speed of “s”, then relative speed is s + 30.
Since it meets the two cars at an interval of 4 minutes, it means it covers a distance of 5kms in 4 minutes or 1/15 hours at a relative speed of “s + 30”.
=> 5 = (s + 30) x 1/15
=> s + 30 = 75
=> s = 45 kmph
This Speed is Relative to a Frame of Reference attached to one of the two moving cars (which are moving with constant velocity of 30kmph).
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