Question

Two cars are traveling in the same direction and the ratio of their speeds is 2:3. The faster car leaves 1 hour after the slower one. In how much time will the former overtake the later?

Answer 1

Answer:

2 hours

Step-by-step explanation:

Given the ratio of the speeds of the car = 2:3

Let the common ratio be x

Speed of 1st car = 2x

Speed of 2nd car = 3x

Let the slower car (1st car) takes time t to meet the faster car (2nd car)

If the distance travelled is d then

$d=2x\times t$

And

$d=3x\times (t-1)$

Thus,

$2x\times t=3x\times (t-1)$

$\implies 2t=3(t-1)$

$\implies t=3$ hour

Therefore, the faster car will overtake the slower car in 3-1 = 2 hours

Hope this helps.