Question

two cars cover the same distance at the speed of 60 and 64 kmps respectively find the distance travelled by them if the slower car takes 1 hour more than the faster car.
A. 906km
B. 960km
C. 960km
D. 966 km​

Answer 1

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore Distance=960\:km}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about two cars cover the same distance at the speed of 60 and 64 kmps respectively.

•. We have to find the distance travelled by them if the slower car takes 1 hour more than the faster car.

$\underline \bold{Given : } \\ \implies Speed \: of \: car \: a \: = 64 \: km/h \\ \\ \implies Speed \: of \: car \: b\: = 60 \: km/h \\ \\ \underline \bold{To \: Find : } \\ \implies Distance \: travelled = ?$

•. According to given question :

$\bold{For \: car \: a : } \\ \implies Distance = speed \times time \\ \\ \implies D= 64 \times t - - - - - (1) \\ \\ \bold{For \: car \: b : } \\ \\ \bold{Condition : It \: takes \: 1 \: hour \: more \: to \: cover \: same \: distance}\\ \implies Distance = speed \times time \\ \\ \implies D = 60 \times (t + 1) - - - - - (2) \\ \\ \bold{comparing \: (1) \: and \: (2)} \\ \implies 64t = 60 \times (t + 1) \\ \\ \implies 64t = 60t + 60 \\ \\ \implies 64t - 60t = 60 \\ \\ \implies 4t = 60 \\ \\ \implies t = \frac{ \cancel{60}}{ \cancel4} \\ \\ \bold{\implies t = 15 \: hour} \\ \\ \bold{putting \: value \: of \: t \: in \: (1)} \\ \implies D = 64 \times 15 \\ \\ \bold{\implies D = 960 \: km} \\ \\ \bold{\therefore Distance \: travelled \: by \: both \: car = 960 \: km}$

Answer 2

Answer:

$\huge\mathfrak\color{red}{Answer:-(960\:km)}$

Given that :-

• two cars cover the same distance at the speed of 60 and 64 kmps respectively

To find :-

• the distance travelled by them if the slower car takes 1 hour more than the faster car.

$\huge\mathfrak{Solution:-}$

=> 60/(64-60)=60/4=15 1 Hr Extra =

15+1=16 60 * 16 = 960

Or

Car A = 60 x ______ y +1

Car b = 64 x ___________ y

$\boxed{Therefore}$

60y + 60 = 64 y

64 -60 y = 60

4y = 60

y = 60/4 =15

60 = x/y +1

60 = x/15+1

60 = x/16

x = 60*16 = 960

$\huge\boxed{960}$