Two cars get closer by 8m every second while travelling in the opposite directions. They get closer by 0.8 m while travelling in the same direction. What are the speed of the two cars?
Answers
Answer:
4.4 , 3.6
Explanation:
In opposite direction speed will add
v1 + v2 = 8/1 = 8
In same direction they subtract
v1 - v2 = 0.8/1 = 0.8
From both eqn,
v1 = 4.4
v2 = 3.6
Answer:
4.4m/s and 3.6m/s
Explanation:
first according to the question the car come closer to each other by 8m every second so their combined speed would be 8m/s if we take it in the frame of either of the cars.
so,
V1+V2=8m/s.---1
next they move closer to each other 0.8m every second when they are moving in the same direction so the velocity of one car in frame of the other car is 0.8m/s.
so,
V1-V2=0.8m/s---2
adding (1) and (2),
V1=4.4m/s.
and by substituting the value of v1 in (1), we get,
4.4+V2=8m/s.
V2=8-4.4m/s,
Therefore,
V2=3.6m/s.
Therefore the answer is 4.4m/s and 3.6m/s.
Hoped you understood,
Thank you.