Question

Two cars initially at rest are free to move the in the x direction car a has mass 4 kg and car b has mass 2kg they are tied together compressing a spring in between them when the spring holding them together is burned car a moves off with a speed of 2 metre per second how much energy was stored in the spring before it was burned​

Answer 1

Thus the energy stored in the spring before it it was burned is 24 J.

Explanation:

According to the law of conservation of momentum:

mAvA+mB+vB=0 [Initially both of them were at rest]

Now find V(B)

vB = −mAvA / mB

= − (4)(2)/(2)

= − 4 m/s

(b) E = 1/2mAv^2(B) + 1/ 2mBv^2(B)

E = 1/2(4)(2)^2 + 1/2(2)(−4)^2

= 24 J

Thus the energy stored in the spring before it it was burned is 24 J.

Also learn about

Find the value of 20 joule on a system which has 10 CM, 1 kg and half minute as the fundamental unit of length mass and time respectively ?

https://brainly.in/question/4178784