Question

Two cars leave a place at the same time and same side. The first car travels 60 km/hour speed. The second car travels 50 km/hr speed at first hour and increases its speed 4 km/hr for every one hour. If both the cars are going towards continuously, then when will the second car overtaking the first car?

Answer 1

dekh cars mat rakh a and b rakh
50 nahi 90 Kar be
mark as BRAINLIEST ANSWERS
First lets start with the simple One -

Velocity - Velocity is speed with Direction or in another words Displacement by time taken. So if a vehicle starts at A and Ends back at point A then the displacement is 0 hence the velocity is 0.

Speed - Assuming the distance between A to B while going from A to B is x kms

Case 1 - The Car goes returns from B to A via the same exact route it went from A to B. So the Average Speed will be total distance travelled by total time taken so .

Total Distance = x + x = 2x

Total Time = x/60 hrs + x/90 hrs = 3X+2X/180 = 5X/180

Average Speed = 2X*180/5X = 360/5 = 72km/hr

Case 2 - The Card goes to A to B via route 1 and returns back via Route 2 so one of the distances is X and the return distance is Y.

so now Average Speed = ((X+Y)/(3X+2Y)) *180

So in Case 2 if you substitute X = Y then also you get 2/5 * 180 = 72 Km / hr.