Question

two cars leave Delhi at the same time travelling in opposite direction if the average speed of one car is 5 kilometre per hour more than that of the other and they are 425 km apart at the end of 5 hours what is the average speed of each​

Answer 1

Let the average speed other car be x

Let the average speed other car be xaverage speed of one car 5km/h

Let the average speed other car be xaverage speed of one car 5km/h so addd up their speeds =x+x+5

Let the average speed other car be xaverage speed of one car 5km/h so addd up their speeds =x+x+5 =(2x+5)

Let the average speed other car be xaverage speed of one car 5km/h so addd up their speeds =x+x+5 =(2x+5)given that:

Let the average speed other car be xaverage speed of one car 5km/h so addd up their speeds =x+x+5 =(2x+5)given that:Time = 5hours

Let the average speed other car be xaverage speed of one car 5km/h so addd up their speeds =x+x+5 =(2x+5)given that:Time = 5hoursDistance = 425km

Let the average speed other car be xaverage speed of one car 5km/h so addd up their speeds =x+x+5 =(2x+5)given that:Time = 5hoursDistance = 425kmDistance =speed/time

Let the average speed other car be xaverage speed of one car 5km/h so addd up their speeds =x+x+5 =(2x+5)given that:Time = 5hoursDistance = 425kmDistance =speed/time(2x+5) 5=425km

Let the average speed other car be xaverage speed of one car 5km/h so addd up their speeds =x+x+5 =(2x+5)given that:Time = 5hoursDistance = 425kmDistance =speed/time(2x+5) 5=425km10x +25=425

Let the average speed other car be xaverage speed of one car 5km/h so addd up their speeds =x+x+5 =(2x+5)given that:Time = 5hoursDistance = 425kmDistance =speed/time(2x+5) 5=425km10x +25=42510x=425-25

Let the average speed other car be xaverage speed of one car 5km/h so addd up their speeds =x+x+5 =(2x+5)given that:Time = 5hoursDistance = 425kmDistance =speed/time(2x+5) 5=425km10x +25=42510x=425-2510x=400

Let the average speed other car be xaverage speed of one car 5km/h so addd up their speeds =x+x+5 =(2x+5)given that:Time = 5hoursDistance = 425kmDistance =speed/time(2x+5) 5=425km10x +25=42510x=425-2510x=400x=40

Let the average speed other car be xaverage speed of one car 5km/h so addd up their speeds =x+x+5 =(2x+5)given that:Time = 5hoursDistance = 425kmDistance =speed/time(2x+5) 5=425km10x +25=42510x=425-2510x=400x=40

Let the average speed other car be xaverage speed of one car 5km/h so addd up their speeds =x+x+5 =(2x+5)given that:Time = 5hoursDistance = 425kmDistance =speed/time(2x+5) 5=425km10x +25=42510x=425-2510x=400x=40 x+5=?

Let the average speed other car be xaverage speed of one car 5km/h so addd up their speeds =x+x+5 =(2x+5)given that:Time = 5hoursDistance = 425kmDistance =speed/time(2x+5) 5=425km10x +25=42510x=425-2510x=400x=40 x+5=?=40+5= 45