Two cars leave Delhi at the same time,travelling in opposite directions. If the average speed of one car is 5 km/hr more than that of the another and they are 425 km apart at the end of 5 hours, what is the average speed of each?
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The two cars are moving in opposite directions, so they are separating at the sum of their speeds.
Looking at the fundamental distance equation, d = rt, we know:
d = 425 km
t = 5 hr
So, the combined rate = 425/5 = 85 km/hr
One car goes 5 km/hr faster than the other, which means we can define their speeds as x and x+5.
x + x+5 = 85
2x +5 = 85
2x = 80
x = 40, which is the speed of one car
x+5 = 45, which is the speed of the other car
Looking at the fundamental distance equation, d = rt, we know:
d = 425 km
t = 5 hr
So, the combined rate = 425/5 = 85 km/hr
One car goes 5 km/hr faster than the other, which means we can define their speeds as x and x+5.
x + x+5 = 85
2x +5 = 85
2x = 80
x = 40, which is the speed of one car
x+5 = 45, which is the speed of the other car
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