Question

Two cars leave one after the other and travel with an acceleration of 0.4 m/s2. Two minutes
after the departure of the first, the distance between the cars becomes 1.9 km. If time
interval between the departure of the cars is a min, then a =​

Answer 1

Answer:

5/6 min

Explanation:

Two cars leave one after the other and travel with an acceleration of 0.4 m/s2. Two minutes

after the departure of the first, the distance between the cars becomes 1.9 km. If time

interval between the departure of the cars is a min, then a =​

Distance covered by First Car in 2 Minutes

S = ut + (1/2)at²

u = 0  from rest   a = 0.4 m/s²  t = 2mins = 120 sec

S = 0 + (1/2)(0.4)*(120)²

=> S = 2880 m

=> S = 2.88 km

distance between the cars = 1.9 km

Other car travelled = 2.88 - 1.9 =  0.98 km = 980 m

Time taken by another car to travel 980 m

980 = (1/2)(0.4)t²

=> t = 70 sec

Another car started after 120 - 70 = 50 sec  = 5/6 min

time

interval between the departure of the cars is a = 5/6 min