two cars left place A and reached place B simultaneously in 2hr. the first car traveled half the distance with 30km/hr and the other half at the speed of 45 km/hr .the second car at the same time covered the entire with a constant acceleration starting from rest.find the acceleration of the second car
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by using simple newton euatuons of motion
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first car reach half distance with 30 km/h
and next half distance with 45 km/h
time taken by 1st car in complete the motion = 2 hrs
Let S is the distance between AB
(S/2)/30 + (S/2)/45 = 2
S{ 1/60 + 1/90} = 2
S × 5 = 360
S = 72 km
now, use formula,
S = ut + 1/2at²
u = 0
S = 72 km
t = 2 hrs
72 = 1/2 × a × 4
a = 36 km/h²
and next half distance with 45 km/h
time taken by 1st car in complete the motion = 2 hrs
Let S is the distance between AB
(S/2)/30 + (S/2)/45 = 2
S{ 1/60 + 1/90} = 2
S × 5 = 360
S = 72 km
now, use formula,
S = ut + 1/2at²
u = 0
S = 72 km
t = 2 hrs
72 = 1/2 × a × 4
a = 36 km/h²
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