Math, asked by dipakauja, 3 months ago

Two cars namely A and B start simultaneously from a certain place at the speed of 40 kmph and 55 kmph, respectively. The car B reaches the destination 2 hours earlier than A. What is the time taken by A to reach the destination?​

Answers

Answered by idiotid8
0

Answer:

Let us assume the distance between starting point and destination is D.

car A will take D/40 hours and car B will take D/55 hours.

As per given condition D/55=D/40-2 .

or D/40-D/55=2

or 55D-40D=2200

or 15D=2200

Hence D=146.666 Km

Step-by-step explanation:

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