Question

Two cars of unequal masses use similar tyres. If thej are moving at the same initial speed,

Answer 1

the distance is same for both cars.. See how : the friction force is mue*m1*g (mue = friction coeff.) for other the friction force is mue*m2*g (mue is same for both as both have same type of tyres) but retardetion due to friction for I car = mue*m1*g/m1 = mue*g for II car = mue*m2*g/m2 = mue*g retardation is same for both , so time taken in stopping will also be same As s = ut+ (at^2)/2