Question

Two cars start at the same time from A and B and travel towards each other at speeds of 50 kmph and 60 kmph respectively. At the time of their meeting the second car has traveled 120 km more than the first. The distance between A and B is:

Answer 1

600 km is the between the cars

Answer 2

Answer:

1320 km

Step-by-step explanation:

Let the distance traveled by first car be x

Since we are given that the second car has traveled 120 km more than the first.

Distance traveled by second car = x+120

First car case

Distance = x

Speed = 50 km/h

$Time = \frac{Distance}{Speed}$

$Time = \frac{x}{50}$

Second car case

Distance = x+120

Speed = 60 km/h

$Time = \frac{Distance}{Speed}$

$Time = \frac{x+120}{60}$

Since the time for which they traveled their respective distances is same

So, $\frac{x}{50} = \frac{x+120}{60}$

$60x =50x+6000$

$60x -50x=6000$

$10x=6000$

$x=600$

So, Total distance between A & B = x+x+120=600+(120+600) = 1320 km

Hence The distance between A and B is 1320 km